> I need to make a table factory function in emacs with cl extension.
> but I'm scheme user. I'm confusing emacs lisp behavior.
> will you please tell me the emacs lisp's free variable issue.

> my table factory function is following code:
>  (defun mk-table-instance ()
>   (let ((table nil)) ;; create a lexical value `table`
>     (defun __temp__ (msg &rest value)
>       ;; some operation changes the lexical variable `table`
>       (case msg
>    ((push) (push (car value) table))
>    (otherwise table)))
>     (function __temp__)))
> ;; return the `__temp__`  procedure with the lexical variable `table`
> ;; i.e. return a closure.

> (fset 'table-object (mk-table-instance))
> ;; 'table-object is an unique procedure object.
> (table-object 'push 13)
> ;; my plan => operate an unique `table` variable which was created by
> involving `mk-table-instance`
> ;; real        => "Debugger entered--Lisp error: (void-variable
> table)"!!!!!!!

> I researched this code. I guess the lexical binded variable `table` in
> `mk-table-instance` procedure refer to the global environment.
> In scheme, the variable refer to the lexical environment.

> How to refer to a lexical environment?